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Monday, February 7, 2011

Submit Form with jQuery and Ajax.

Submit Form with jQuery and Ajax.
submitting HTML form values without refreshing page using jQuery and Ajax.






<script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.3.0/jquery.min.js"></script>
<script type="text/javascript" >
$(function() {
$(".submit").click(function() {
var name = $("#name").val();
var username = $("#username").val();
var password = $("#password").val();
var dataString = 'name='+ name + '&username=' + username + '&password=' + password;

if(name=='' || username=='' || password=='')
{
$('.success').fadeOut(200).hide();
$('.error').fadeOut(200).show();
}
else
{
$.ajax({
type: "POST",
url: "insert.php",
data: dataString,
success: function(){

$('.success').fadeIn(200).show();
$('.error').fadeOut(200).hide();

}
});
}
return false;
});
});
</script>


<form method="post" name="form">
<input id="name" name="name" type="text" />
<input id="username" name="username" type="text" />
<input id="password" name="password" type="password" />

<input type="submit" value="Submit" class="submit"/>
<span class="error" style="display:none"> Please Enter Valid Data</span>
<span class="success" style="display:none"> Registration Successfully</span>
<div id="display" align="left">

///---Insert.php
<?php
if($_POST)
{
$name=$_POST['name'];
$username=$_POST['username'];
$password=$_POST['password'];
/* mysql_query("SQL insert statement......."); */
}else { }

?>

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