Django how to create RSS feeds for the blog application

Django how to create RSS feeds for the blog application

RSS is an abbreviation for Really Simple Syndication, it’s a way to have information delivered to you instead of you having to go find it. RSS is basically a structured XML document that includes full or summarized text along with other metadata such as published date, author name, etc.

RSS is a web feed allows users and applications to access updates to websites in a standardized, computer-readable format.

In this article, we are going to generate feeds for a blog application

Part 1 : Django Build a blog application with bootstrap and Automatically Generate slugs

https://tutorial101.blogspot.com/2020/05/django-build-blog-application-with.html

Part 2 : Django Build a blog application Part 2 with WYSIWYG Editor Pagination and Comments

https://tutorial101.blogspot.com/2020/05/django-build-blog-application-part-2.html

 
#models.py
from django.db import models
 
from django.contrib.auth.models import User
from django.utils.text import slugify

STATUS = (
    (0,"Draft"),
    (1,"Publish")
)

class Post(models.Model):
    title = models.CharField(max_length=200, unique=True)
    slug = models.SlugField(max_length=200, unique=True)
    author = models.ForeignKey(User, on_delete= models.CASCADE,related_name='myapp_post')
    updated_on = models.DateTimeField(auto_now= True)
    content = models.TextField()
    created_on = models.DateTimeField(auto_now_add=True)
    status = models.IntegerField(choices=STATUS, default=0)
 
    class Meta:
        ordering = ['-created_on']

    def __str__(self):
        return self.title
  
    def get_absolute_url(self):
        from django.urls import reverse
        return reverse("post_detail", kwargs={"slug": str(self.slug)})
  
    class Meta:  
        db_table = "myapp_post"
  
    def save(self, *args, **kwargs):
        value = self.title
        self.slug = slugify(value, allow_unicode=True)
        super().save(*args, **kwargs)

Create a new file feeds.py inside the application directory.

 
#feeds.py
from django.contrib.syndication.views import Feed
from django.template.defaultfilters import truncatewords
from myapp.models import Post
from django.urls import reverse


class LatestPostsFeed(Feed):
    title = "My blog"
    link = ""
    description = "New posts of my blog."

    def items(self):
        return Post.objects.filter(status=1)

    def item_title(self, item):
        return item.title

    def item_description(self, item):
        return truncatewords(item.content, 30)

    # Only needed if the model has no get_absolute_url method
    # def item_link(self, item):
    #     return reverse("post_detail", args=[item.slug])

The title, link, and description correspond to the standard RSS

from .feeds import LatestPostsFeed

urlpatterns = [
    path("feed/rss", LatestPostsFeed(), name="post_feed"),
               ]

RSS 2.0 feed at /feed/rss
navigate to http://127.0.0.1:8000/feed/rss you should see the XML file.

To explore more visit – https://docs.djangoproject.com/en/3.0/ref/contrib/syndication/